Protokoll tmp/e149_01_P.txt
XXXXXXXXXXXXXXXXXXXXXXXXXXX
XXX  P R O T O K O L L  XXX
XXXXXXXXXXXXXXXXXXXXXXXXXXX

tmp/e149_01

Tmri: ../img_reg3d/beispiele3D/atlas01.c3d
Mask: 
StartU1: 
StartU2: 
StartU3: 

inner iterations:           79 in  0 days 00:00:03.20 +  0 days 00:10:17
distance (finally)       D = 5.544280e-04 M0
resolution_now:              0
smooth_now:              t = 0.025000
Hoehe x Breite x Ebenen des Bildes: 128 x 256 x 166 

_P_a_r_a_m_e_t_e_r_
resolution_start:            3
resolution_end:              0
resolution: Interpolation U: fft
resolution: Interpol Images: lin
Interpolation der Bilder:    bicub
Histogrammausgleich Tmri: Box = 0, Grauwerte = 256

Glaettung mit der Waermeleitungsgleichung
  RWA glaetten, trig. Trafo: fft
  smooth_start:  0.200000
  smooth_factor: 0.500000
  smooth_end:    0.025600
  smooth_max:    1000
smooth_place:  1
grad2DrExp:    0.00
grad2DtExp:    0.00

extra_rand:    0

_A_b_s_t_a_n_d_s_m_a_s_s_
Mass = 0
Theoretisch richtig in d: Phi( Nabla( T )) statt praktisch   Nabla( Phi( T ))

_R_e_g_u_l_a_r_i_s_i_e_r_u_n_g_
RWA regularisierung: fft
    r = 2.500000e+00
 beta = 2

_K_o_n_t_r_o_l_l_p_u_n_k_t_e_
use_fixedpoints:            0
use_weakpoints_everystep:   0

_L_i_n_i_e_n_s_u_c_h_e_
use_cg:            1
line_start:        1.000
line_step:         0.500
line_steps_max:    8
line_max_smallest: 2
curved_mindestabstieg: 0.9500
reg_alpha: 0.000e+00

randTU = [0, 0, 0; 0, 0, 0]

randGemeinsam = [0, 57, 0; 0, 57, 0]

_V_e_r_l_a_u_f:_
  iter resolution t_smooth  count  time
     2  1/ 8  3.200000e+00     2   0 days 00:00:01.37
     4  1/ 8  1.600000e+00     2   0 days 00:00:01.02
     5  1/ 8  8.000000e-01     1   0 days 00:00:00.51
     6  1/ 8  4.000000e-01     1   0 days 00:00:00.52
     7  1/ 8  2.000000e-01     1   0 days 00:00:00.51
     8  1/ 8  1.000000e-01     1   0 days 00:00:00.51
     9  1/ 8  5.000000e-02     1   0 days 00:00:00.51
    10  1/ 8  2.500000e-02     1   0 days 00:00:00.51
    11  1/ 8  1.250000e-02     1   0 days 00:00:00.48
    12  1/ 8  6.250000e-03     1   0 days 00:00:00.49
    13  1/ 8  3.125000e-03     1   0 days 00:00:00.48
    15  1/ 4  6.400000e+00     2   0 days 00:00:02.82
    17  1/ 4  3.200000e+00     2   0 days 00:00:02.41
    19  1/ 4  1.600000e+00     2   0 days 00:00:02.40
    21  1/ 4  8.000000e-01     2   0 days 00:00:02.35
    23  1/ 4  4.000000e-01     2   0 days 00:00:02.38
    25  1/ 4  2.000000e-01     2   0 days 00:00:02.38
    27  1/ 4  1.000000e-01     2   0 days 00:00:02.40
    29  1/ 4  5.000000e-02     2   0 days 00:00:02.38
    31  1/ 4  2.500000e-02     2   0 days 00:00:02.37
    33  1/ 4  1.250000e-02     2   0 days 00:00:02.38
    35  1/ 4  6.250000e-03     2   0 days 00:00:02.42
    37  1/ 2  1.280000e+01     2   0 days 00:00:08
    39  1/ 2  6.400000e+00     2   0 days 00:00:08
    41  1/ 2  3.200000e+00     2   0 days 00:00:08
    43  1/ 2  1.600000e+00     2   0 days 00:00:08
    45  1/ 2  8.000000e-01     2   0 days 00:00:08
    47  1/ 2  4.000000e-01     2   0 days 00:00:08
    49  1/ 2  2.000000e-01     2   0 days 00:00:08
    51  1/ 2  1.000000e-01     2   0 days 00:00:08
    53  1/ 2  5.000000e-02     2   0 days 00:00:08
    55  1/ 2  2.500000e-02     2   0 days 00:00:08
    57  1/ 2  1.250000e-02     2   0 days 00:00:08
    59  1/ 1  2.560000e+01     2   0 days 00:00:41
    61  1/ 1  1.280000e+01     2   0 days 00:00:43
    63  1/ 1  6.400000e+00     2   0 days 00:00:42
    65  1/ 1  3.200000e+00     2   0 days 00:00:42
    67  1/ 1  1.600000e+00     2   0 days 00:00:42
    69  1/ 1  8.000000e-01     2   0 days 00:00:41
    71  1/ 1  4.000000e-01     2   0 days 00:00:41
    73  1/ 1  2.000000e-01     2   0 days 00:00:42
    75  1/ 1  1.000000e-01     2   0 days 00:00:42
    77  1/ 1  5.000000e-02     2   0 days 00:00:42
    79  1/ 1  2.500000e-02     2   0 days 00:00:42

sum(verlaufD)/lenght(verlaufD) = 0.006900985

 END