Protokoll ergebnisse/v146_05_P.txt XXXXXXXXXXXXXXXXXXXXXXXXXXX XXX P R O T O K O L L XXX XXXXXXXXXXXXXXXXXXXXXXXXXXX ergebnisse/v146_05 Rmri: beispiele3D/CG_MRT_cor.c3d Tmri: beispiele3D/atlas02e144_02.c3d Mask: StartU1: StartU2: StartU3: beispiele3D/atlas06_u3.c3d inner iterations: 186 in 0 days 00:01:10 + 0 days 00:50:17 distance (finally) D = 1.960122e-06 M1 resolution_now: 0 smooth_now: t = 0.230584 Hoehe mal Breite mal Tiefe: 128 x 256 x 256 _P_a_r_a_m_e_t_e_r_ resolution_start: 2 resolution_end: 0 resolution: Interpolation U: fft resolution: Interpol Images: lin Interpolation der Bilder: linear Threshold R s = 0.200000 Threshold T s = 0.060000 Histogrammausgleich, histR = 0.000000 Histogrammausgleich, histT = 0.000000 Vorglaettung von Rmri gauss 0 Vorglaettung von Tmri gauss 0 Gammakorrektur von Rmri mit 1.000000 Gammakorrektur von Tmri mit 1.000000 Histogrammausgleich Rmri: Box = 32, Grauwerte = 256 Histogrammausgleich Tmri: Box = 32, Grauwerte = 256 Glaettung mit der Waermeleitungsgleichung RWA glaetten, trig. Trafo: fft smooth_start: 0.100000 smooth_factor: 0.800000 smooth_end: 0.256000 smooth_max: 10000 smooth_place: 1 grad3DrExp: 0.00 grad3DtExp: 0.00 extra_rand: 0 _A_b_s_t_a_n_d_s_m_a_s_s_ Mass = 1 Theoretisch richtig in d: Phi( Nabla( T )) statt praktisch Nabla( Phi( T )) _R_e_g_u_l_a_r_i_s_i_e_r_u_n_g_ RWA regularisierung: fft r = [4.000, 3.500, 3.000] beta = 1.000 _K_o_n_t_r_o_l_l_p_u_n_k_t_e_ use_fixedpoints: 0 use_weakpoints_everystep: 0 _L_i_n_i_e_n_s_u_c_h_e_ use_cg: 1 line_start: 1.000 line_step: 0.500 line_steps_max: 8 line_smallest: 0.400 line_max_smallest: 2 curved_mindestabstieg: 0.9900 reg_alpha: 0.000e+00 randTU = [0, 0, -12; 0, 0, -11] randGemeinsam = [0, 57, 33; 0, 57, 34] V e r l a u f: iter resolution t_smooth count time 19 1/ 4 3.200000e+00 19 0 days 00:00:13 44 1/ 4 2.560000e+00 25 0 days 00:00:18 46 1/ 4 2.048000e+00 2 0 days 00:00:01.75 48 1/ 4 1.638400e+00 2 0 days 00:00:01.76 50 1/ 4 1.310720e+00 2 0 days 00:00:01.79 52 1/ 4 1.048576e+00 2 0 days 00:00:01.78 54 1/ 4 8.388608e-01 2 0 days 00:00:01.78 56 1/ 4 6.710886e-01 2 0 days 00:00:01.79 58 1/ 4 5.368709e-01 2 0 days 00:00:01.78 60 1/ 4 4.294967e-01 2 0 days 00:00:01.78 62 1/ 4 3.435974e-01 2 0 days 00:00:01.76 64 1/ 4 2.748779e-01 2 0 days 00:00:01.76 66 1/ 4 2.199023e-01 2 0 days 00:00:01.76 68 1/ 4 1.759219e-01 2 0 days 00:00:01.77 70 1/ 4 1.407375e-01 2 0 days 00:00:01.76 72 1/ 4 1.125900e-01 2 0 days 00:00:01.79 74 1/ 4 9.007199e-02 2 0 days 00:00:01.78 76 1/ 4 7.205759e-02 2 0 days 00:00:01.79 78 1/ 4 5.764608e-02 2 0 days 00:00:01.77 99 1/ 2 6.400000e+00 21 0 days 00:02:06 101 1/ 2 5.120000e+00 2 0 days 00:00:15 103 1/ 2 4.096000e+00 2 0 days 00:00:14 105 1/ 2 3.276800e+00 2 0 days 00:00:14 107 1/ 2 2.621440e+00 2 0 days 00:00:14 109 1/ 2 2.097152e+00 2 0 days 00:00:14 114 1/ 2 1.677722e+00 5 0 days 00:00:30 116 1/ 2 1.342177e+00 2 0 days 00:00:14 118 1/ 2 1.073742e+00 2 0 days 00:00:14 120 1/ 2 8.589935e-01 2 0 days 00:00:14 123 1/ 2 6.871948e-01 3 0 days 00:00:18 125 1/ 2 5.497558e-01 2 0 days 00:00:14 127 1/ 2 4.398047e-01 2 0 days 00:00:15 129 1/ 2 3.518437e-01 2 0 days 00:00:14 131 1/ 2 2.814750e-01 2 0 days 00:00:14 133 1/ 2 2.251800e-01 2 0 days 00:00:14 135 1/ 2 1.801440e-01 2 0 days 00:00:14 137 1/ 2 1.441152e-01 2 0 days 00:00:14 139 1/ 2 1.152922e-01 2 0 days 00:00:14 149 1/ 1 1.280000e+01 10 0 days 00:07:42 151 1/ 1 1.024000e+01 2 0 days 00:01:49 154 1/ 1 8.192000e+00 3 0 days 00:02:36 156 1/ 1 6.553600e+00 2 0 days 00:01:49 158 1/ 1 5.242880e+00 2 0 days 00:01:49 160 1/ 1 4.194304e+00 2 0 days 00:01:43 162 1/ 1 3.355443e+00 2 0 days 00:01:48 164 1/ 1 2.684355e+00 2 0 days 00:01:55 166 1/ 1 2.147484e+00 2 0 days 00:01:49 168 1/ 1 1.717987e+00 2 0 days 00:01:50 170 1/ 1 1.374390e+00 2 0 days 00:01:49 172 1/ 1 1.099512e+00 2 0 days 00:01:50 174 1/ 1 8.796093e-01 2 0 days 00:01:43 176 1/ 1 7.036874e-01 2 0 days 00:01:42 178 1/ 1 5.629500e-01 2 0 days 00:01:56 180 1/ 1 4.503600e-01 2 0 days 00:01:56 182 1/ 1 3.602880e-01 2 0 days 00:01:56 184 1/ 1 2.882304e-01 2 0 days 00:01:56 186 1/ 1 2.305843e-01 2 0 days 00:01:56 sum(verlaufD)/lenght(verlaufD) = 0.011639143 END